Code For Posting (for post xml to another page)

Code For Posting

To post XML, use the following function:

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   WebRequest req = null;
   WebResponse rsp = null;
   try
   {
    string fileName = "C:\test.xml";
    string uri = "http://localhost/PostXml/Default.aspx";
    req = WebRequest.Create(uri);
    //req.Proxy = WebProxy.GetDefaultProxy(); // Enable if using proxy
    req.Method = "POST";        // Post method
    req.ContentType = "text/xml";     // content type
    // Wrap the request stream with a text-based writer
    StreamWriter writer = new StreamWriter(req.GetRequestStream());
    // Write the XML text into the stream
    writer.WriteLine(this.GetTextFromXMLFile(fileName));
    writer.Close();
    // Send the data to the webserver
    rsp = req.GetResponse();
    
   }
   catch(WebException webEx)
   {
    
   }
   catch(Exception ex)
   {
    
   }
   finally
   {
    if(req != null) req.GetRequestStream().Close();
    if(rsp != null) rsp.GetResponseStream().Close();
   }Function to read xml data from local system
  /// <summary>
  /// Read XML data from file
  /// </summary>
  /// <param name="file"></param>
  /// <returns>returns file content in XML string format</returns>
  private string GetTextFromXMLFile(string file)
  {
   StreamReader reader = new StreamReader(file);
   string ret = reader.ReadToEnd();
   reader.Close();
   return ret;
  }

Code For Reading Posted Data

Now, on the Web server in the ASP.NET page, write the following code to access the posted data:

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private void Page_Load(object sender, EventArgs e)
  {
     page.Response.ContentType = "text/xml";
    // Read XML posted via HTTP
    StreamReader reader = new StreamReader(page.Request.InputStream);
    String xmlData = reader.ReadToEnd(); 
}

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License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

S Sansanwal


Member

Occupation:	Architect
Location:	Australia